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.ÿþSolution for Chapter 22(compiled by Xinkai Wu)A.Exercise 22.1 Non-resonant Particle Energy in Wave [Chris Hirata/00]The rate of change of the non-resonant electron kinetic energy is given bydUe d 1= mev2F0dvdt dt 21 "F0= mev2 dv2 "tusing eq.(22.20)1 " "F0 "F0= mev2 - D - v dv2 "v "v "zthe 2nd term in the square brackets gives zero b/c it s odd in v;also, integrate by part gives"F0= Dmev dv (1)"vNow the D appearing the above expression should be the difference betweeneq.(22.21) and eq.(22.22).It s not hard to see this corresponds to, for non-Érresonant electrons with v [ Pobierz caÅ‚ość w formacie PDF ]
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